1Find the value of k for which the pair of linear equations ka+3y-k-2 – InterviewSolution

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1Find the value of k for which the pair of linear equations ka+3y-k-2 and12x+hy-k has no solution

Answer»

k(kx+3y=k-23(12x+ky=k

k^2x+3ky=k^2-2k36x+3ky=3k

For no solution, lines must be parallelSo, k^2=36; k=6,-6and k^2-2k not equal to 3k

k^2-2k=3kk^2-5k=0k(k-5)=0k=0,5(no contradiction) So k should be 6,-6

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