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`1F` of electricity is passed through `10 L` of a solution of aqueous solution of `NaCl` . Calculate the `pH` of the solution. |
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Answer» Aqueous `NaCl` solution on electrolysis gives `Cl_(2)(g)` at anode and `H_(2)(g)` at cathode and `overset(c-)(O)H` ions in the solution. `1F=1` equilvalent of `H_(2)(g)=1` equivalent of `Cl_(2)(g)` and `=1`Equivalent of `overset(c-)(O)H` ions `:. [overset(c-)(O)H]=("Equivalent")/("Volume of solution in L")=(1)/(10L)=10^(-1)N` or `M` `:. pOH=-log (10^(-1))=1` `pH=14-1=13` |
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