1a) The radius of a circle is 10 cm. Its one chord is 16 cm long, Find

1.	1a) The radius of a circle is 10 cm. Its one chord is 16 cm long, Find theperpendicular distance of this chord from the centre
Answer» Given that, Radius of circle (OA) = 10cm Chord (AB) = 16cm DrawOC⊥AB We know that The perpendicular from centre to chord bisects the chord The perpendicular from centre to chord bisects the chord ∴AC=BC=16/2=8cm Now inΔOCA, by Pythagoras theorem AC^2+ OC^2= OA^2 =>8^2+ OC^2= 10^2 =>64 + OC^2= 100 =>OC^2= 36 => OC^2= 36 =>OC =6cm

1a) The radius of a circle is 10 cm. Its one chord is 16 cm long, Find theperpendicular distance of this chord from the centre

Answer»

Given that,

Radius of circle (OA) = 10cm

Chord (AB) = 16cm

DrawOC⊥AB

We know that

The perpendicular from centre to chord bisects the chord

∴AC=BC=16/2=8cm

Now inΔOCA, by Pythagoras theorem

AC^2+ OC^2= OA^2

=>8^2+ OC^2= 10^2

=>64 + OC^2= 100

=>OC^2= 36

=> OC^2= 36

=>OC =6cm