helloheating effect produced by an electric current, I through a CONDUCTOR of RESISTANCE, R for a time, t is given by H = I2Rt. This equation is called the Joule's equation of ELECTRICAL heating. b)The resistance of the filament used in the bulb. A 2.5 kW immersion heater is used to heat water.Explanation:Introduction When current flows through a conductor, heat energy is generated in the conductor. The heating effect of an electric current depends on three factors: The resistance, R of the conductor. A higher resistance produces more heat. The time, t for which current flows. The LONGER the time the larger the amount of heat produced The amount of current, I. the higher the current the larger the amount of heat generated. Hence the heating effect produced by an electric current, I through a conductor of resistance, R for a time, t is given by H = I2Rt. This equation is called the Joule’s equation of electrical heating. Electrical energy and power The work done in pushing a charge round an electrical circuit is given by w.d = VIt So that power, P = w.d /t = VI The electrical power consumed by an electrical appliance is given by P = VI = I2R = V2/R Example An electrical bulb is labeled 100W, 240V. Calculate: a)The current through the filament when the bulb WORKS normally b)The resistance of the filament used in the bulb. Solution I = P/V = 100/240 = 0.4167A R = P/I2 = 100/ 0.41672 = 576.04Ω or R = V2/P =2402/100 = 576Ωhope it helped youplz make me brainliest