19 In the given figure PO II ST, -POR- <110°, and RST-130° find -ORS

1.	19 In the given figure PO II ST, -POR- <110°, and RST-130° find -ORSfigure PC) 11 ST. <pQR-<1100, and RST-130°find <QRS
Answer» A line XY parallel to PQ and ST is drawn. ∠PQR+∠QRX= 180° (Angles on the same side of transversal.)⇒110° + ∠QRX= 180°⇒∠QRX= 70° Also,∠RST+ ∠SRY= 180° (Angles on the same side of transversal.)⇒130° + ∠SRY= 180°⇒∠SRY= 50° Now,∠QRX+∠SRY+∠QRS = 180°⇒70°+ 50°+ ∠QRS= 180°⇒∠QRS= 60° Thank you

19 In the given figure PO II ST, -POR- <110°, and RST-130° find -ORSfigure PC) 11 ST. <pQR-<1100, and RST-130°find <QRS

Answer»

A line XY parallel to PQ and ST is drawn.

∠PQR+∠QRX= 180° (Angles on the same side of transversal.)⇒110° + ∠QRX= 180°⇒∠QRX= 70°

Also,∠RST+ ∠SRY= 180° (Angles on the same side of transversal.)⇒130° + ∠SRY= 180°⇒∠SRY= 50°

Now,∠QRX+∠SRY+∠QRS = 180°⇒70°+ 50°+ ∠QRS= 180°⇒∠QRS= 60°

Thank you