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19.7kg of gold was recovered from smuggler.The number of atoms of gold recovered are:(Au=197) |
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Answer» Explanation: given mass , m =19.7 kg N= no. of atoms A= avogadro no. molar mass , M= 197 m/M=N/A 19.7/197 =N/6.022×10^23 0.1×6.022×10^23 = 6.022×10^22 atoms u can ALSO convert kg into gram |
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