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18gm water is added in a 200 gm sample of Oleum labeled as `109%`. The new labelling of the final sample is :A. `106%`B. `103%`C. `100%`D. `0%` |
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Answer» Correct Answer - C Minimum labelling of Oleum `= 100%` All free `SO_(3)` is exhausted using `18gm` of water and pure `218gm H_(2)SO_(4)` formed. |
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