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18g of water is takento prepare the tea. Find out the internal energy of vaporisation at `100^(@)`C. `(Delta_(vap)H` for water at 373 K 373 K is `40.66kJ mol^(-1))`A. `37.56kJmol^(-1)`B. `-37.56kJmol^(-1)`C. `43.76kJmol^(-1)`D. `3-43.76kJmol^(-1)` |
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Answer» Correct Answer - A 18g water=mol water `H_(2)O(l)hArrH_(2)O(g)` `DeltaH=DeltaE+Deltan_(g)RT` `40.66=DeltaE+(1xx8.314xx373)/(1000)` `DeltaE=40.66-3.1` `DeltaE=+2xx(2)-(3)` |
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