18. The sum of five consecutive numbers is 190, What is thesum of the

1.	18. The sum of five consecutive numbers is 190, What is thesum of the largest and the smallest numbers?(1) 75(4) 73(2) 77(5) of these(3) 76ito nositive integers is 462.
Answer» Let the five consecutive numbers are x-2,x-1,x,x+ 1,x+ 2. Sum of numbers = 190 Therefore, x - 2 + x - 1 + x + x + 1 + x + 2 = 190 = 5x = 190 Therefore, x = 38 Sum of largest and smallest numbers = 190 x+2+x-2= 2x= 2*38= 76Answer = 76Please like the solution 👍 ✔️

18. The sum of five consecutive numbers is 190, What is thesum of the largest and the smallest numbers?(1) 75(4) 73(2) 77(5) of these(3) 76ito nositive integers is 462.

Answer»

Let the five consecutive numbers are x-2,x-1,x,x+ 1,x+ 2.

Sum of numbers = 190

Therefore, x - 2 + x - 1 + x + x + 1 + x + 2 = 190

= 5x = 190

Therefore, x = 38

Sum of largest and smallest numbers = 190

x+2+x-2= 2x= 2*38= 76Answer = 76Please like the solution 👍 ✔️