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18. The radii of two concentric circles are 13cma tangent to the smaller circle touching it aircles are 13cm and 8cm. AB is tangent of a bigger Circle. BD ist D. Find the length of AB

Answer»

from right triangle BOD

BD = √(OB²-OD²) = √(13²- 8²) = √105

from right triangle POD

PD = √(OP²-OD²) = √(13²-8²) = √105

PB = BD + PD = 2√105 PB²= 420

from right triangle APB

AP = √(AB²- PB²) =√26²- 420 = √676-420 = √256 = 16



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