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18. The radii of two concentric circles are 13cma tangent to the smaller circle touching it aircles are 13cm and 8cm. AB is tangent of a bigger Circle. BD ist D. Find the length of AB |
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Answer» from right triangle BOD BD = √(OB²-OD²) = √(13²- 8²) = √105 from right triangle POD PD = √(OP²-OD²) = √(13²-8²) = √105 PB = BD + PD = 2√105 PB²= 420 from right triangle APB AP = √(AB²- PB²) =√26²- 420 = √676-420 = √256 = 16 |
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