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18 The 4th term of an AP is zero. Prove thatthe 25th term of the AP is three times its[CBSE 2016]11th term. |
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Answer» Given a^4 = 0 That is (a + 3d) = 0 ⇒ a = - 3d ........... (1) nth term of AP is given by an = a + (n – 1)d a^11 = a + 10d = – 3d + 10d = 7d [From (1)] a^25 = a+ 24d = – 3d + 24d = 21d [From (1)] = 3 x 7d Hence a^25 = 3 x a^11 |
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