18. Initially the system is at rest. From the instance shown, 2m*2m' is projected towards pulley with speed u. Find thespeed of 'm' just after the string becomes taut.(A) 2u/3(B) 4u/3(C) u(D) 5u/3

18. Initially the system is at rest. From the instance shown, 2m*2m'

1.	18. Initially the system is at rest. From the instance shown, 2m*2m' is projected towards pulley with speed u. Find thespeed of 'm' just after the string becomes taut.(A) 2u/3(B) 4u/3(C) u(D) 5u/3
Answer» SPEED uExplanation:Mass 2m MOVES forward without Acceleration at VELOCTY u Till string is not Taut . It also means String gets Taut when falling Mass m gets a VELOCITY u . Soon after string become Taut Mass has velocity u.

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18. Initially the system is at rest. From the instance shown, 2m*2m' is projected towards pulley with speed u. Find thespeed of 'm' just after the string becomes taut.(A) 2u/3(B) 4u/3(C) u(D) 5u/3​

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18. Initially the system is at rest. From the instance shown, 2m*2m' is projected towards pulley with speed u. Find thespeed of 'm' just after the string becomes taut.(A) 2u/3(B) 4u/3(C) u(D) 5u/3