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18. In fig, ABCD and ABEF are parallelograms. The area of the Parallelogram ABCD is 90 sq cm. Find(a) ar (ABEF)(b) ar (ABD)(c) ar (BEF)OR |
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Answer» Area of given ABCD parallelogram is 90 cm. (i) area of rectangle ABEF = area of parallelogram ABCD because , one common side is AB of parallelogram and rectangle and hight of both parallelogram is same as Breadth of rectangle .hence, area of rectangle ABEF = 90 cm² (ii) area of ABD = half of area of parallelogram { see attachment it is clear that , diagonal is divided by two equal of parallelogram, here BD is diagonal , that's why are(ABD) = ar(ABCD)/2 } hence, ar(ABD) = 90cm²/2 = 45 cm² (iii) ar(BEF) = half of ar(ABEF) = 45 cm² [ similarly diagonal of rectangle divide its two equal part ] |
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