18 g of glucose is dissolved in 90 g of water. The relative lowering of vapour pressure is equal to ………….

18 g of glucose is dissolved in 90 g of water. The relative lowering o

1.	18 g of glucose is dissolved in 90 g of water. The relative lowering of vapour pressure is equal to ………….
Answer» <P> Solution :`0.1 ` `(P^(@) -P)/(P ^(@)) = x _(2) impliesx_(2) =` No. of moles of GLUCOSE `= (18)/(180) =0.1` `therefore (P^(@) -P)/(P^(@)) =0.1`