18 g of glucose is dissolved in 1 kg of water in a saucepan

1.	18 g of glucose is dissolved in 1 kg of water in a saucepan
Answer» Answer: 373.202 K Explanation: Moles of glucose= 18 G /180 g MOL -1 =0.1mol No of kilograms of solvent =1 kg Thus molality of glucose solution = 0.1mol kg -1 For water , change in BOILING POINT ATb = Kb * m = 0.52 K kg mol -1 * 0.1 mol kg-1= 0.052 K Since water boils at 373.15 K at 1.013 bar pressure , therefore,the boiling point of solution will be 373.15 + 0.052 = 373.202 K.

Answer»

Answer:

373.202 K

Explanation:

Moles of glucose= 18 G /180 g MOL -1 =0.1mol

No of kilograms of solvent =1 kg

Thus molality of glucose solution = 0.1mol kg -1

For water , change in BOILING POINT

ATb = Kb * m = 0.52 K kg mol -1 * 0.1 mol kg-1= 0.052 K

Since water boils at 373.15 K at 1.013 bar pressure , therefore,the boiling point of solution will be 373.15 + 0.052 = 373.202 K.

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