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18. Find the sum of first 100 even natural numbers which are divisible by 5. |
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Answer» Step-by-step EXPLANATION: even NATURAL number which is divisible by 5 is 10,20,30,40........ a=10,d=10,n=100(first 100 even natural number) sn=n/2(2a+(n-1) d) =100/2(2*10+(100-1)10) =50(20+990)=50*1010 =50500 is the correct answer |
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