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18. Find the sum of first 100 even natural numbers which are divisible by 5.​

Answer»

Step-by-step EXPLANATION:

even NATURAL number which is divisible by 5 is

10,20,30,40........

a=10,d=10,n=100(first 100 even natural number)

sn=n/2(2a+(n-1) d)

=100/2(2*10+(100-1)10)

=50(20+990)=50*1010

=50500 is the correct answer



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