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18. A bicycle moves with a constant velocity of 5 km/h for 10 minutes and then decelerates at the rate1 km/h, till it stops. Find the total distance coveredby the bicycle.24 |
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Answer» y of bicycle (U) = 5 km / hr time TAKEN (t) = 10 minutes =10/60 hr = 1/6 hr DECELERATION ( use negative sign) = -1 km /hr^2as we know , speed formula let the initial distance covered = D1 d1 = u*t. (distance[d]=speed[u]*time[t]5*1/65/6 km = d1let the final distance covered be d2 , final velocity will become (v)acc. to question :by formula v^2 - u^2 = 2as we have v = 0 ( as it have to be stopped given) putting values (0)^2 - (5)^2 = 2*-1 * d2. as s = d225 = -2 * d2 d2 = 25/ -2 km total distance = d1 + d2 |
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