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18.4 g of `N_(2)O_(4)` is taken in a 1 L closed vessel and heated till the equilibrium is reached. `N_(2)O_(4(g))rArr2NO_(2(g))` At equilibrium it is found that 50% of `N_(2)O_(4)` is dissociated . What will be the value of equilibrium constant?A. 0.2B. 2C. 0.4D. 0.8 |
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Answer» Correct Answer - C `{:(,N_(2)O_(4(g)),hArr,2NO_(2(g))),("Intial conc.",18.4,,0),("No. of moles",(18.4)/(92)=0.2,,),("At equilibrium",0.2-0.1,,2xx0.1),(,=0.1,,=0.2):}` `K_(c)=(0.2xx0.2)/(0.1)=0.4` |
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