1.

18, 12 जनवरी, 1979 को कौन दिन था?Which day was on 12" January, 1979?

Answer»

As 12th January 1979 = 1900 years + 78 years + period from 1st Jan. to 12 Jan. 1979

So No. of odd days in 1600 years = 0

No. of odd days in 300 years (1900 " 1600) = (5 * 3) ÷ 7 = 2 weeks + 1 odd day

No. of odd days in 78 years = 19 leap year + 59 ordinary years

= {(19 * 2) + (59 *1)} ÷ 7= (38 + 59) ÷ 7 = 97 ÷ 7 =13 weeks + 6 odd days

No. of odd days in period from 1st Jan. to 12 Jan. 1979 = 12 days = 12 ÷ 7 = 1 week + 5 odd days

Total odd days = 1 + 6 + 5 = 12 days = 12 ÷ 7 = 1 week + 5 odd days

So 12th January 1979 is Friday as Sunday is 0; Monday is 1 and so on.

12 odd days+ up to 1978 ::1600 has 0 odd days.300 has 1 odd day.so total 13 days+ in 78::19 leap years has 38 and 59 days for normal years. so totally59+38+13=110%7 (per week)=5 that is friday



Discussion

No Comment Found