18.0 g of water completely vaporises at 100^(@)C and 1 bar pressure and the enthalpy change in the process is40.79 kJ mol^(-1). What will be the enthalpychange for vaporising two moles of water under the same conditions ? What is the standard enthalpy of vaporisation for water ?

18.0 g of water completely vaporises at 100^(@)C and 1 bar pressure an

1.	18.0 g of water completely vaporises at 100^(@)C and 1 bar pressure and the enthalpy change in the process is40.79 kJ mol^(-1). What will be the enthalpychange for vaporising two moles of water under the same conditions ? What is the standard enthalpy of vaporisation for water ?
Answer» Solution :`18.0` g of WATER `=` 1 mole `:. ` Standard ENTHALPY of vaporisation at`100^(@)C` and 1 bar pressure `=40.79 kJ MOL^(-1)` Enthalpy change in vaporisationof 2 moles of water `= 2 xx 40.79 kJ = 81. 58 kJ`