17. An alpha particle is placed in an electric field of 15 x 10^4NC^-1

1.	17. An alpha particle is placed in an electric field of 15 x 10^4NC^-1. Calculate the force on the particleAns. 4.8 x 10^-14N
Answer» Given that , Charge (q) = 2e = 3.2 × (10)^-19 C ELECTRIC FIELD (E) = 15 x 10^4 N/c As we KNOW that , The electric FORCE per unit charge is called electric field Mathematically , $\large \sf\fbox{Electric \: field \: ( E) = \frac{F}{q} }$ The SI unit of electric field is N/c Thus , F = 15 x 10^4 × 3.2 × (10)^-19 F = 48 × (10)^-15 F = 4.8 × (10)^-14 N $\therefore\sf \underline{The \: electric \: force \: is \: 4.8 \times {(10)}^{ - 14} \: N}$

17. An alpha particle is placed in an electric field of 15 x 10^4NC^-1. Calculate the force on the particleAns. 4.8 x 10^-14N

Answer»

Given that ,

Charge (q) = 2e = 3.2 × (10)^-19 C

ELECTRIC FIELD (E) = 15 x 10^4 N/c

As we KNOW that ,

The electric FORCE per unit charge is called electric field

Mathematically ,

$\large \sf\fbox{Electric \: field \: ( E) = \frac{F}{q} }$

The SI unit of electric field is N/c

Thus ,

F = 15 x 10^4 × 3.2 × (10)^-19

F = 48 × (10)^-15

F = 4.8 × (10)^-14 N

$\therefore\sf \underline{The \: electric \: force \: is \: 4.8 \times {(10)}^{ - 14} \: N}$

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17. An alpha particle is placed in an electric field of 15 x 10^4NC^-1. Calculate the force on the particleAns. 4.8 x 10^-14N​

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17. An alpha particle is placed in an electric field of 15 x 10^4NC^-1. Calculate the force on the particleAns. 4.8 x 10^-14N