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[17(2-y)-5(y+12)]/1-7y=8 |
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Answer» ong>Step-by-step explanation: 17(2-y)-5(y+12)/1-7y=8 We move all terms to the LEFT: 17(2-y)-5(y+12)/1-7y-(8)=0 We add all the numbers together, and all the variables 17(-1y+2)-5(y+12)/1-7y-8=0 We add all the numbers together, and all the variables -7y+17(-1y+2)-5(y+12)/1-8=0 We multiply parentheses -7y-17y-5(y+12)/1+34-8=0 We multiply all the terms by the denominator -7y*1-17y*1-5(y+12)+34*1-8*1=0 We add all the numbers together, and all the variables -7y*1-17y*1-5(y+12)+26=0 We multiply parentheses -7y*1-17y*1-5y-60+26=0 Wy multiply elements -7y-17y-5y-60+26=0 We add all the numbers together, and all the variables -29y-34=0 We move all terms CONTAINING y to the left, all other terms to the right -29y=34 y=34/-29 y=-1+5/29
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