1.

17,.1 Prove thatcote-tan0=sinecose

Answer»

CosA/sinA - sinA/cosA=(2cos2A-1)/sinAcosAlhs:cos^2A-sin^2A/sinAcosA cos^2A-1+1-sin^2A/sinAcosAcos^2A-1+cos^A/sinAcosA 2cos^2a-1/sinAcosA=rhs



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