1.

17.1 gms of Al_(2)(SO_(4))_(3) is present in 500 ml of aqueous solution. It.s concentration can be

Answer»

0.1 M
0.6 N
1 N
0.5 M

SOLUTION :`M=(17.1)/(342xx0.5)=0.1M=0.6N`


Discussion

No Comment Found