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| 1. |
16x -10/x =27 by quadric formula |
| Answer» We have, {tex}16x - \\frac{{10}}{x} = 27{/tex}{tex}\\Rightarrow \\frac{{16{x^2} - 10}}{x} = 27{/tex}{tex}\\Rightarrow{/tex} 16x2 - 10 = 27x{tex}\\Rightarrow{/tex} 16x2 - 27x - 10 = 0{tex}\\Rightarrow{/tex} 16x2 - 32x + 5x - 10 = 0{tex}\\Rightarrow{/tex} 16x(x - 2) + 5(x - 2) = 0{tex}\\Rightarrow{/tex} (16x + 5)(x - 2) = 0{tex}\\Rightarrow{/tex} (16x + 5) = 0 or (x - 2) = 0{tex}\\Rightarrow x = - \\frac{{ 5}}{{16}}{/tex} or, x = 2Hence, the roots of given quadratic equation are 2 and\xa0{tex}-\\frac{{5}}{16}{/tex} | |