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-16*x - x^2 %2B x^4 %2B 4*x^3 - 12 |
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Answer» x^4 + 4x^3 - x^2 - 16x - 12 = x^4 + x^3 + 3x^3 + 3x^2 - 4x^2 - 4x - 12x - 12 = x^3(x + 1) + 3x^2(x + 1) - 4x(x + 1) - 12(x + 1) = (x + 1)(x^3 + 3x^2 - 4x - 12) = (x + 1)(x^3 + 2x^2 + x^2 + 2x - 6x - 12) = (x + 1)(x^2(x + 2) + x(x + 2) - 6(x + 2)) = (x + 1)(x + 2)(x^2 + x - 6) = (x + 1)(x + 2)(x^2 + 3x - 2x - 6) = (x + 1)(x + 2)(x(x + 3) - 2(x + 3)) = (x + 1)(x + 2)(x + 3)(x - 2) |
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