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16. If (x + 1) is the HCF of (ax2 + bx + c) and(bx? + ax + c), then the value of c is(a) 0(b) 2(d) 3(c) 1 |
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Answer» If (x + 1) is HCF of (ax^2 + bx + c) and (bx^2 + ax + c) Then,For x = - 1 both these equations should be equal to 0 Hence,a - b + c = 0..... (1)b - a + c = 0......(2) Add eq(1) and eq(2)2c = 0c = 0 (a) is correct option |
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