16 g ot solid SulphurCalculate the number of aluminium ions present in

1.	16 g ot solid SulphurCalculate the number of aluminium ions present in 0.051aluminium oxide11.g ot(Hint: The mass of an ion is the same as that of an atom of thesame element. Atomic mass of Al = 27 u)SCIEN
Answer» Molecular weight of Al2O3= 102 g 102 g of Al2O3contains 6.022X10^23molecules 0.051g of Al2O3contain X number of molecules X = 0.051 X 6.022X10^23/102 = 0.003 X 10^20 X = 3 X 10^20 1 molecule of Al2O3contains – 2 Al+3ions 3 X 10^20molecules contains – 2 X 3 X 10^20 = 6 X 10^20Al+3ions∴0.051 g of Al2O3contains 6 X 10^20Al+3ions

16 g ot solid SulphurCalculate the number of aluminium ions present in 0.051aluminium oxide11.g ot(Hint: The mass of an ion is the same as that of an atom of thesame element. Atomic mass of Al = 27 u)SCIEN

Answer»

Molecular weight of Al2O3= 102 g

102 g of Al2O3contains 6.022X10^23molecules

0.051g of Al2O3contain X number of molecules

X = 0.051 X 6.022X10^23/102 = 0.003 X 10^20

X = 3 X 10^20

1 molecule of Al2O3contains – 2 Al+3ions

3 X 10^20molecules contains – 2 X 3 X 10^20

= 6 X 10^20Al+3ions∴0.051 g of Al2O3contains 6 X 10^20Al+3ions