16 g of oxygen has same number of molecules as in

1.	16 g of oxygen has same number of molecules as in
Answer» 16 g of CO 28 g of `N_(2)` 14 g of `N_(2)` 1.0 g of `H_(2)` Solution :The calculation of molecule can be done as follows : NUMBER of molecules `= ("Mass")/("Molar mass") XX "Avogadro"` No. of molecules , in 16 g oxygen `=(16)/(32) xx N_(A)=(N_(A))/(3)` In 16 g of `CO=(16)/(32)xxN_(A)=(N_(A))/(1.75)` In 28 g of `N_(2) = (28)/(28) xx N_(A)=N_(A)` In 14 g of `N_(2) = (14)/(28)xx N_(A) = (N_(A))/(2)` In 1 g of `H_(2)=(1)/(2) xx N_(A) = (N_(A))/(2)` HENCE, 16 g of `O_(2)= 14 g` of `N_(2) = 1.0 g ` of `H_(2)`

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