16 g of an ideal gas SO_(X) occupies 5.6 L at S.T.P. What is its molecular mass ? What is the value of X ?

16 g of an ideal gas SO_(X) occupies 5.6 L at S.T.P. What is its molec

1.	16 g of an ideal gas SO_(X) occupies 5.6 L at S.T.P. What is its molecular mass ? What is the value of X ?
Answer» SOLUTION :5.6 L of the GAS at S.T.P weigh = 16 g 22.4 L of the gas at S.T.P. weigh `= ((1.6g))/((5.6L))xx(22.4L)=64G` By definition, molar mass of gas `(SO_(X))=64g` `:. 32+x(16)=64or16x=64-32=32orx=2` Value of x = 2 and the gas `= SO_(2)`