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16), Find i ICF of 81 and 237 and express it us a linear combination of 81 and 237, le HCF (81,237)-81x+237yfor some x and y |
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Answer» By Euclid's Division Algorithm, 237=81(2)+(75) 81=75(1) + (6) 75=6(12)+(3) 6=3(2)+(0) Hcf =3 Expressing it in the form of 237x+81y=HCF 3=75-6(12) { From 2nd last step} 3=75-(81-75)(12) {Substituting} 3=75-(81*12-75*12) 3=75-81*12+75*12 3=75(13)-81(12) 3=(237-81*2)(13)-81(12) 3=237(13)-81(38) 3=237(13)+81(-38) {we need an expression in the form 237x + 81y } Therefore, x =13 , y =- 38 |
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