15cm^(3) of hydrocarbonrequires 45cm^(3) of oxygen for complete combustion and 30cm^(3) of CO_(2) is formed. The formula of hydrocarbon is

15cm^(3) of hydrocarbonrequires 45cm^(3) of oxygen for complete combus

1.	15cm^(3) of hydrocarbonrequires 45cm^(3) of oxygen for complete combustion and 30cm^(3) of CO_(2) is formed. The formula of hydrocarbon is
Answer» `C_(3)H_(6)` `C_(2)H_(2)` `C_(4)H_(10)` `C_(2)H_(4)` Solution :`C_(x)H_(y)+(x+(y)/(4))O_(2)rarr xCO_(2)+(y)/(2)H_(2)O` `{:("15 ml","45 ml","30 ml"),("1 ml","3 ml","2 ml"):}` `therefore x=2` `x+(y)/(4)=3 rArr (y)/(4)=1` `"hydrocarbon is "C_(2)H_(4)`