1535. In the Fig., ABCD is a parallelogram in which:BAO 35°, ZDAO 40�

1.	1535. In the Fig., ABCD is a parallelogram in which:BAO 35°, ZDAO 40° and ZCOD- 105°. Find:(i) <ABO (ii) <ODC (iii) LACB (iv) <CBD105°40°35°
Answer» in triangle AOB, angle AOB + angle ABO + Angle BAO=180°ANGLE AOB = ANGLE COD= 105° (vertically opposite angles)=>angle ABO = 180°-35°-105°=40° angle ABD = angle BDC=angle ODC=40°(alternate interior angles where AB\|\|DC) angleACB=angle CAD=40°(alternate interior angles)in triangle CBO, angle BOC=75°(supplementary pair)therefore angle CBO=180°-75°-40°=65°

1535. In the Fig., ABCD is a parallelogram in which:BAO 35°, ZDAO 40° and ZCOD- 105°. Find:(i) <ABO (ii) <ODC (iii) LACB (iv) <CBD105°40°35°

Answer»

in triangle AOB, angle AOB + angle ABO + Angle BAO=180°ANGLE AOB = ANGLE COD= 105° (vertically opposite angles)=>angle ABO = 180°-35°-105°=40°

angle ABD = angle BDC=angle ODC=40°(alternate interior angles where AB||DC)

angleACB=angle CAD=40°(alternate interior angles)in triangle CBO, angle BOC=75°(supplementary pair)therefore angle CBO=180°-75°-40°=65°