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15. Two taps A and B together fill a swimming poolin 15 hours. Taps A and Bare kept open for12 hours and then tap B is closed. It takesanother 8 hours for the swimming pool to befilled. How many hours does each tap require tofill the swimming pool? |
Answer» ✪ Question :-❦ Two taps A and B together fill a swimming pool in 15 hours. Taps A and BARE kept open for 12 hours and then TAP B is CLOSED. It takes another 8 hours for the swimming pool to be filled. How many hours does each tap require to fill the swimming pool ? ✰ Solution :-it is given that, Both Tap A and B can will the pool in 15 hours . That means , we can say that, ➺ (A + B) = 1/15 . ( per hour they fill ). Now, Both are opened for 12 hours and than B is closed , that means Rest was filled by A ALONE in 8 more hours . So, ⟿ 12(A+B) + 8A = 1 ( TOTAL ) Putting value of (A+B) here , we get, ⟿ 12 * (1/15) + 8A = 1 ⟿ 4/5 + 8A = 1 ⟿ 8A = 1 - 4/5 ⟿ 8A = 1/5 ⟿ A = 1/(5*8) ⟿ A = 1/40.So, A will Fill alone the swimming pool in 40 hours. ____________________________________Now, putting This value we get, ➳ A + B = 1/15 ➳ 1/40 + B = 1/15 ➳ B = 1/15 - 1/40 ➳ B = (8 - 3) /120 ➳ B = 5/120 ➳ B = 1/24So, A will Fill alone the swimming pool in 24 hours. _____________ |
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