1.

15. Two taps A and B together fill a swimming poolin 15 hours. Taps A and Bare kept open for12 hours and then tap B is closed. It takesanother 8 hours for the swimming pool to befilled. How many hours does each tap require tofill the swimming pool?​

Answer»

Question :-

❦ Two taps A and B together fill a swimming pool

in 15 hours. Taps A and BARE kept open for

12 hours and then TAP B is CLOSED. It takes

another 8 hours for the swimming pool to be

filled. How many hours does each tap require to

fill the swimming pool ?

Solution :-

it is given that, Both Tap A and B can will the pool in 15 hours .

That means , we can say that,

➺ (A + B) = 1/15 . ( per hour they fill ).

Now, Both are opened for 12 hours and than B is closed , that means Rest was filled by A ALONE in 8 more hours .

So,

⟿ 12(A+B) + 8A = 1 ( TOTAL )

Putting value of (A+B) here , we get,

12 * (1/15) + 8A = 1

⟿ 4/5 + 8A = 1

⟿ 8A = 1 - 4/5

⟿ 8A = 1/5

⟿ A = 1/(5*8)

⟿ A = 1/40.

So, A will Fill alone the swimming pool in 40 hours.

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Now, putting This value we get,

A + B = 1/15

➳ 1/40 + B = 1/15

➳ B = 1/15 - 1/40

➳ B = (8 - 3) /120

➳ B = 5/120

➳ B = 1/24

So, A will Fill alone the swimming pool in 24 hours.

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