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15. The ratio of the difference in energy between the first and the second Bohr orbit to that between the second and the third Bohr orbit is Options: (a) rises continuously (b) remains unchanged in the process (c) first rises and then falls to the original position (d) first falls and then rises to the original position [ans :d]

Answer» ION :For H-atomE3=−13.632E3=−13.632=−13.69=−13.69=−1.5eV=−1.5eVE2=−13.622E2=−13.622=−13.64=−13.64=−3.4eV=−3.4eVE1=−13.612E1=−13.612=−13.61=−13.61=−13.6eV=−13.6eVNow E2−E1=(−3.4)−(−13.6)E2−E1=(−3.4)−(−13.6)=13.6−3.4=10.2eV=13.6−3.4=10.2eVE3−E2=(−1.5)−(3.4)E3−E2=(−1.5)−(3.4)=3.4−1.5=1.9eV=3.4−1.5=1.9eV∴E2−E1E3−E2=10.21.9∴E2−E1E3−E2=10.21.9eVeV=5.4=275


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