15. The equation of the line passing through the pointB (2, 2) and whi

1.	15. The equation of the line passing through the pointB (2, 2) and which is farthest from the pointA (0,0) is given by(1) y = x\|(2) x + y = 4(3) y = 2x(4) X = 2y
Answer» Answer: helo GUYS its your answer Step-by-step explanation: + 3Y - 5) + λ (x + y - 2) = 0 , of all these lines one line is farthest from point (7,4) ... INTERSECTION point of given lines is (1,1) ... The SLOPE of the line which is perpendicular to 2y=x +1 is −

15. The equation of the line passing through the pointB (2, 2) and which is farthest from the pointA (0,0) is given by(1) y = x|(2) x + y = 4(3) y = 2x(4) X = 2y

Answer»

Answer:

helo GUYS its your answer

Step-by-step explanation:

+ 3Y - 5) + λ (x + y - 2) = 0 , of all these lines one line is farthest from point (7,4) ... INTERSECTION point of given lines is (1,1) ... The SLOPE of the line which is perpendicular to 2y=x +1 is −

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15. The equation of the line passing through the pointB (2, 2) and which is farthest from the pointA (0,0) is given by(1) y = x|(2) x + y = 4(3) y = 2x(4) X = 2y​

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15. The equation of the line passing through the pointB (2, 2) and which is farthest from the pointA (0,0) is given by(1) y = x|(2) x + y = 4(3) y = 2x(4) X = 2y