1.

15 moles of H_(2) and 5.2 moles of I_(2) are mixed and allowed to attain equlibrium at 500^(@)C. At equlibrium, the concentration of HI is found to be 10 moles. The equlibrium constant for the formation of HI is

Answer»

50
15
100
25

Solution :`{:(H_(2)" "+" "I_(2)" "HARR" "2HI),(15""5.2""0),((15-5)" "(5.2-5)""10):}`
`K_(C)=([HI]^(2))/([H_(2)][I_(2)])=(10xx10)/(10xx0.2)=50`


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