15, in a regular pentagon ABCDE, find each angle of △ACD

1.	15, in a regular pentagon ABCDE, find each angle of △ACD
Answer» in pentagon there 5 side.Sum of all interior angle in polygon with n side is (n-2)× 180 .In Pentagon is 3 × 180 = 540In regular pentagon all angle are equal so let each angle be x so 5x = 540 x = 540/5 = 108 Thankd

Answer»

in pentagon there 5 side.Sum of all interior angle in polygon with n side is (n-2)× 180 .In Pentagon is 3 × 180 = 540In regular pentagon all angle are equal so let each angle be x

so 5x = 540 x = 540/5 = 108

Thankd

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15, in a regular pentagon ABCDE, find each angle of △ACD

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