15. Ilow many terms of the G.P. 33069ate needed to give the sus512h th

1.	15. Ilow many terms of the G.P. 33069ate needed to give the sus512h the midunoi nf the line segment
Answer» a = 3 r = 1/2 Sum of n terms in a GP = a(1-r^n)/(1-r) So 3069/512 = 3(1-(1/2)^n)/(1-1/2) 3069/51232 = 1- (1/2)^n 3069/3072 = 1- (1/2)^n (1/2)^n = 1- 3069/3072 (1/2)^n = 3/3072 (1/2)^n = 1/1024 (1/2)^n = (1/2)^10 Solving this equation we get the value of n = 10 Like my answer if you find it useful! thnxx😘😘😘

15. Ilow many terms of the G.P. 33069ate needed to give the sus512h the midunoi nf the line segment

Answer»

a = 3

r = 1/2

Sum of n terms in a GP =

a(1-r^n)/(1-r)

3069/512 = 3(1-(1/2)^n)/(1-1/2)

3069/512*3*2 = 1- (1/2)^n

3069/3072 = 1- (1/2)^n

(1/2)^n = 1- 3069/3072

(1/2)^n = 3/3072

(1/2)^n = 1/1024

(1/2)^n = (1/2)^10

Solving this equation we get the value of n = 10

Like my answer if you find it useful!

thnxx😘😘😘