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15. \( \frac{d y}{d x}+\frac{y^{2}+1}{x^{2}+1}=0 \) |
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Answer» \(\frac{dy}{dx}+\frac{y^2+1}{x^2+1}=0\) ⇒ \(\frac{dy}{y^2+1}+\frac{dx}{x^2+1}=0\) ⇒ tan-1y + tan-1x = c (On integrating both sides) |
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