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15.0g of an unknown molecular material is dissolved in 450g of water. The resulting solution freezes at -0.34^(@)C. What is the molar mass of the material? K_(f) for water = 1.86K kg mol^(-1). |
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Answer» SOLUTION :`W_(("SOLVENT"))=15.0g` ` W_(("solvent")) =450g` `Delta T_(f) = T_(1) ^(0) - T_(f) =0-(-0.34)=0.34^(@)C` `Delta T_(f)= k _(f) m` `0.34 =1.86 xx (15)/(M) xx (1000)/(450)` `M = (1.86 xx 15 xx 1000)/(0.34 xx 450) = 182. 35 g MOL^(-1).` |
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