Saved Bookmarks
| 1. |
14:The ratio of the length of the parallel sides of a trapezium is 4: 1. The distance between themis 10 cm. If the area of the trapezium is 500 cm”, find the lengths of the parallel sides. |
|
Answer» Let the sides be 4x and x Given h=10 cm A=500cm^2 Now, Area is given as 500 =1/2 × 10 × (4x+x) 500 =10 × 5x 50x = 500 x= 500 / 50 = 10 4x = 4 × 10 = 40 x = 10 = 10 the parallel sides are 40 cm and 10 cm. solve(14)-Given that. b:a=4:1let be, b=4x. and. a=x h=10cm. Area(A)=500cm^2formula of area of trapezium, A=(a+b)h/2500=(4x+x)10/2500=5x*5 after transfar 5*5500/5*5=x20=xb=4*x=4*20=80cma=x=20cm if any doubt then ask me 500 |
|