14*. In an isosceles triangle, length of the congruent sides is 13 cm

1.	14*. In an isosceles triangle, length of the congruent sides is 13 cm and its base is10 cm. Find the distance between the vertex opposite the base and the centroid.
Answer» Step-by-step explanation: If ABC is an isosceles triangle the congruent sides AB=AC and BC the base.The vertex AD where POINT D dvides the base in 2 equal sides, BD=DC From the right angle triangle ADCWE calculate the vertex AD of triangle ABC. AD^2=AC^2-DC^2 where DC=AC/2=10/2=5 AD^2=13^2-5^2 AD=sqrt144 AD=12 . The CENTROID of an isosceles triangle is at the DISTANCE of 1/3 of the vertex from the base. Then if G is the centroid on the vertex AD The distance from base GD is 1/3×12=4 GD=4 DEADSOUL

14*. In an isosceles triangle, length of the congruent sides is 13 cm and its base is10 cm. Find the distance between the vertex opposite the base and the centroid.

Answer»

Step-by-step explanation:

If ABC is an isosceles triangle the congruent sides AB=AC and BC the base.The vertex AD where POINT D dvides the base in 2 equal sides,

BD=DC From the right angle triangle ADCWE calculate the vertex AD of triangle ABC.

AD^2=AC^2-DC^2 where DC=AC/2=10/2=5

AD^2=13^2-5^2 AD=sqrt144 AD=12 .

The CENTROID of an isosceles triangle is at the DISTANCE of 1/3 of the vertex from the base.

Then if G is the centroid on the vertex AD

The distance from base GD is 1/3×12=4

GD=4

DEADSOUL

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