1.

14. In a triangle ABC, AB = 6, BC = 8 andAC = 10. A perpendicular dropped from B.meets in side AC at D. A circle of radiusBD (with center B) is drawn. If the circlecuts AB and BC at P and Q, respectively,then AP:QC is equal to:(a) 1:1(b) 3:2(c) 4:1(d) 3:8

Answer»

Answer:

Option D,

3:8

Step-by-step explanation:

Area of TRIANGLE ABC = 1/2 x 6 x 8 = 24 sq.units

Area of triangle ABD = 1/2 x 10 x BD = 24

BD = 4.8

AP= 6 - 4.8 = 1.2

QC = 8 - 4.8 =3.2

AP/QC = 1.2/3.2 = 3/8

answer: 3:8



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