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14. If sum of the squares of zeroes of the quadratic polynomial plx)t k is 40, find thevalue of k |
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Answer» p (x)= x^2-8x+kp (x)=Ax^2+Bx+C(The equation is inthis form) Let the zeroes be 'a' and 'b' It is given that=> a^2+b^2=40=> (a+b)^2 - 2ab = 40 ----1 sum of zeroes=> a+b = -B/A = -(-8)/1 = 8 Product of zeroes => a*b = C/A = k Substitute these values in the equation1 we get=> 8^2 - 2k = 40=> 64 - 2k = 40=> 2k = 24=> k = 12 |
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