1.

14. If sum of the squares of zeroes of the quadratic polynomial plx)t k is 40, find thevalue of k

Answer»

p (x)= x^2-8x+kp (x)=Ax^2+Bx+C(The equation is inthis form)

Let the zeroes be 'a' and 'b'

It is given that=> a^2+b^2=40=> (a+b)^2 - 2ab = 40 ----1

sum of zeroes=> a+b = -B/A = -(-8)/1 = 8

Product of zeroes => a*b = C/A = k

Substitute these values in the equation1 we get=> 8^2 - 2k = 40=> 64 - 2k = 40=> 2k = 24=> k = 12



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