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14. If cos (A+B) = 0, and B = 30', then find the value of sin(A - B). |
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Answer» ANSWER cos(α+β)=0⇒cos(α+β)=COS90(∵cos0=0)⇒α+β=90⇒α=90−βsin(α−β)=SIN(90−2β)=cos2β (∵sin(90−θ)=cosθ) |
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