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14. If α and β are zeros of P(y) = 5y2-7y + 1 , find α + β . |
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Answer» Given : 5y² -7y + 1 a and b are zeroes so, a + b = -(-7)/5 = 7/5 ab = 1/5 So, 1/a + 1/b (a + b)/ab (7 × 5)/5 = 7 Ans: 7 |
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