14.7 g of sulphuric acid was needed to dissolve 16.8 g of a metal. Calculate the equivalent weight of the metal and the volume of hydrogen liberated at NTP.

14.7 g of sulphuric acid was needed to dissolve 16.8 g of a metal. Cal

1.	14.7 g of sulphuric acid was needed to dissolve 16.8 g of a metal. Calculate the equivalent weight of the metal and the volume of hydrogen liberated at NTP.
Answer» SOLUTION :56, 3.36 LITRES