135. In a rectangle ABCD, AB = 25 cm and BC = 15. In what ratio doesth

1.	135. In a rectangle ABCD, AB = 25 cm and BC = 15. In what ratio doesthe bisector of ZC divide AB?
Answer» Answer: 2 : 3 Step-by-step explanation: in a rectangle ABCD AB=25 cm BC=15 cm in what ratio bisector of angle C divide AB Let say CE is bisector of angle C ∠C = 90° Bisector of ∠C = 45° in Δ CEB ∠BCE = 45° & ∠B = 90° => Tan 45° = BE /BC => 1 = BE/15 => BE = 15 cm AB = 25 cm AB = AE + BE => 25 = AE + 15 => AE = 10 cm AE : BE :: 10 : 15 => AE : BE :: 2 : 3 bisector of angle C divide AB in 2:3 ratio

135. In a rectangle ABCD, AB = 25 cm and BC = 15. In what ratio doesthe bisector of ZC divide AB?

Answer»

Answer:

2 : 3

Step-by-step explanation:

in a rectangle ABCD AB=25 cm BC=15 cm in what ratio bisector of angle C divide AB

Let say CE is bisector of angle C

∠C = 90°

Bisector of ∠C = 45°

in Δ CEB

∠BCE = 45° & ∠B = 90°

=> Tan 45° = BE /BC

=> 1 = BE/15

=> BE = 15 cm

AB = 25 cm AB = AE + BE

=> 25 = AE + 15

=> AE = 10 cm

AE : BE :: 10 : 15

=> AE : BE :: 2 : 3

bisector of angle C divide AB in 2:3 ratio