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134. One year ago, a man was 8 timesas old as his son. Now his age isequal to the square of his son's age.Find their present ages. |
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Answer» Answer: Step-by-step explanation: let age of son one yr ago be X age of man one yr ago be 8x ..... age of son after one year = x+1 age of man after one year = 8x+1 .... now accordind to question.. 8x+1= (x+1)^2 8x+1=x^2 + 1 +2x after solving 8x = x^2 +2x now...x^2 - 6x=0 solving this we get ...x=0 and x = 6 but age CANT be zero...so..x=6... age of son is x+1 = 7 years and age of man be 8x+1= 49...ANS.. |
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